Y=(1)^2+4x

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Solution for Y=(1)^2+4x equation: 



=(1)^2+4Y

We move all terms to the left:

-((1)^2+4Y)=0

We get rid of parentheses

-4Y-1^2=0

We add all the numbers together, and all the variables

-4Y-1=0

We move all terms containing Y to the left, all other terms to the right

-4Y=1

Y=1/-4

Y=-1/4

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